float llPow(float base, float exp)

Raise a number to an exponent.

The number to raise.

The exponent to raise the base to.

The result of raising base to exp.

• If the base is negative, the exponent must have no decimals (i.e. represent an integer number); otherwise, NaN is returned.
• If both base and exponent are zero, the result is 1.0.
• If either argument is NaN, the result is NaN.

float f;
f = llPow(1, 444);    // sets f to 1
f = llPow(0, 5);      // sets f to 0
f = llPow(5, 0);      // sets f to 1
f = llPow(0, 0);      // sets f to 1
f = llPow(2.7182818, 3); // raises 2.7182818 (the Euler constant) to the 3rd power,
                         // storing the result (approx. 20.085540) in f
f = llPow(-0.5, 4);   // sets f to 0.0625
f = llPow(-1.5, 1.5); // sets f to NaN because the base is negative and the exponent has decimals

• llLog calculates the natural logarithm of the input.
• llLog10 calculates the logarithm in base 10 of the input.