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types:list [2017-09-30 07:10 SLT] sei Fix data memory handling related to variables |
types:list [2021-02-01 09:00 SLT] (current) sei Info on passing lists by reference |
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| Line 124: | Line 124: | ||
| list A = (list)"X"; | list A = (list)"X"; | ||
| // This only adds 4 bytes to the list, because constant | // This only adds 4 bytes to the list, because constant | ||
| - | // strings are reusable if they have been used | + | // strings are reused if they have been used |
| // to assign them to some list element that | // to assign them to some list element that | ||
| // still contains the unmodified string, in this | // still contains the unmodified string, in this | ||
| // case the first element of the list: | // case the first element of the list: | ||
| A += "X"; | A += "X"; | ||
| - | // This adds 18 bytes to the list because the | + | // This adds 20 bytes to the list because the |
| // string that results from a calculation is not | // string that results from a calculation is not | ||
| // reused, even if it matches an existing | // reused, even if it matches an existing | ||
| Line 144: | Line 144: | ||
| </code> | </code> | ||
| - | Basically, the rule isn't whether the strings are equal, but whether they are handled verbatim without applying operations to them. The same trick doesn't work with keys, though. | + | Basically, the rule isn't whether the strings are equal, but whether they are handled verbatim without applying operations to them. The same trick fails with other types, including keys; adding e.g. a key variable to a list multiple times, results in one new instance of the key being counted for every addition. Same happens for integers, for example. But extracting them as lists still works. |
| + | |||
| + | Lists are passed by reference to functions, meaning that when passing a list to a function, a new copy is not created, but instead the same list is used. | ||
| === Limits === | === Limits === | ||